Medium
There is a robot on an m x n grid. The robot is initially located at the top-left corner (i.e., grid[0][0]). The robot tries to move to the bottom-right corner (i.e., grid[m - 1][n - 1]). The robot can only move either down or right at any point in time.
Given the two integers m and n, return the number of possible unique paths that the robot can take to reach the bottom-right corner.
The test cases are generated so that the answer will be less than or equal to 2 * 109.
Example 1:

Input: m = 3, n = 7
Output: 28
Example 2:
Input: m = 3, n = 2
Output: 3
Explanation: From the top-left corner, there are a total of 3 ways to reach the bottom-right corner:
Right -> Down -> Down
Down -> Down -> Right
Down -> Right -> Down
Constraints:
1 <= m, n <= 100func uniquePaths(m int, n int) int {
	dp := make([][]int, m)
	for i := range dp {
		dp[i] = make([]int, n)
		dp[i][0] = 1
	}
	for j := 0; j < n; j++ {
		dp[0][j] = 1
	}
	for i := 1; i < m; i++ {
		for j := 1; j < n; j++ {
			dp[i][j] = dp[i-1][j] + dp[i][j-1]
		}
	}
	return dp[m-1][n-1]
}