LeetCode-in-Go

71. Simplify Path

Medium

Given a string path, which is an absolute path (starting with a slash '/') to a file or directory in a Unix-style file system, convert it to the simplified canonical path.

In a Unix-style file system, a period '.' refers to the current directory, a double period '..' refers to the directory up a level, and any multiple consecutive slashes (i.e. '//') are treated as a single slash '/'. For this problem, any other format of periods such as '...' are treated as file/directory names.

The canonical path should have the following format:

Return the simplified canonical path.

Example 1:

Input: path = “/home/”

Output: “/home”

Explanation: Note that there is no trailing slash after the last directory name.

Example 2:

Input: path = “/../”

Output: “/”

Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go.

Example 3:

Input: path = “/home//foo/”

Output: “/home/foo”

Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.

Example 4:

Input: path = “/a/./b/../../c/”

Output: “/c”

Constraints:

Solution

func simplifyPath(path string) string {
	stk := make([]string, 0)
	start := 0
	for start < len(path) {
		for start < len(path) && path[start] == '/' {
			start++
		}
		end := start
		for end < len(path) && path[end] != '/' {
			end++
		}
		s := path[start:end]
		if s == ".." {
			if len(stk) > 0 {
				stk = stk[:len(stk)-1]
			}
		} else if s != "." && s != "" {
			stk = append(stk, s)
		}
		start = end + 1
	}
	if len(stk) == 0 {
		return "/"
	}
	ans := ""
	for _, s := range stk {
		ans += "/" + s
	}
	return ans
}