Easy
Given two stings ransomNote
and magazine
, return true
if ransomNote
can be constructed from magazine
and false
otherwise.
Each letter in magazine
can only be used once in ransomNote
.
Example 1:
Input: ransomNote = “a”, magazine = “b”
Output: false
Example 2:
Input: ransomNote = “aa”, magazine = “ab”
Output: false
Example 3:
Input: ransomNote = “aa”, magazine = “aab”
Output: true
Constraints:
1 <= ransomNote.length, magazine.length <= 105
ransomNote
and magazine
consist of lowercase English letters.func canConstruct(ransomNote string, magazine string) bool {
charCount := make([]int, 26)
n := len(ransomNote)
for i := 0; i < n; i++ {
charCount[ransomNote[i]-'a']++
}
for i := 0; i < len(magazine) && n != 0; i++ {
if charCount[magazine[i]-'a'] > 0 {
n--
charCount[magazine[i]-'a']--
}
}
return n == 0
}